Question

Divide 112 into two parts such that one fourth of the one part may exceed one-third of other part by 7.​

Answer 1

Step-by-step explanation:

112 divided 7 answer 16

Answer 2

The two parts are 76 and 36

Given :

The number 112

To find :

Divide 112 into two parts such that one fourth of the one part may exceed one-third of other part by 7.

Solution :

Step 1 of 2 :

Form the equation

Let first part = x

Then second part = 112 - x

By the given condition

$\displaystyle \sf{ \frac{x}{4} = \frac{(112 - x)}{3} + 7}$

Step 2 of 2 :

Find the parts

$\displaystyle \sf{ \frac{x}{4} = \frac{(112 - x)}{3} + 7}$

$\displaystyle \sf{ \implies \frac{x}{4} - \frac{(112 - x)}{3} = 7}$

$\displaystyle \sf{ \implies \frac{3x - 4(112 - x)}{12} = 7}$

$\displaystyle \sf{ \implies \frac{3x - 448 + 4x}{12} = 7}$

$\displaystyle \sf{ \implies \frac{7x - 448 }{12} = 7}$

$\displaystyle \sf{ \implies 7x - 448 = 84}$

$\displaystyle \sf{ \implies 7x = 448 + 84}$

$\displaystyle \sf{ \implies 7x = 532}$

$\displaystyle \sf{ \implies x = \frac{532}{7} }$

$\displaystyle \sf{ \implies x = 76 }$

First part = 76

Second part = 112 - 76 = 36

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ The product of two successive multiples of 5 is 300. What are the values of these multiples?

https://brainly.in/question/26660243

2. the product of two successive multiples of 10 is 1200 . then find these multiples

https://brainly.in/question/28616922