Question

Divide 1162 into three parts such that 4 times the first part, 5 times the second part and 7 times the third part are equal.

Answer 1

x+y+z=1162

4x=5y=7z

      (x+y+z=1162)*4                              to eliminate x
 4x+4y+4z=4648
 5y+4y+4z=4648
      (9y+4z=4648)*7/4                           to eliminate z
(63/4)y+7z=8134
(63/4)y+5y=8134
      (83/4)y= 8134
            83y=32536
                y=392

              4x=5y
              4x=1960
                x=490

              7z=5y
              7z=1960
                z=280

Therefore, x=490, y=392 and z=280.

Answer 2

Answer:

Step-by-step explanation:

4x=5y=7z=k

x=k/4, y=k/5, z=k/7

x:y:z=k/4:k/5:k/7

Or 1/4:1/5:1/7

35:28:20(multiply by LCM ie 140)

x=(35/83)×1162=₹490