Divide 1162 into three parts such that 4 times
the first is equal to 5 times the second and 7
times the thitd. Find the value of smallest part.
Answers
Answered by
7
Step-by-step explanation:
X+y+z=1162
4x=5y=7z
(x+y+z=1162)*4 to eliminate x
4x+4y+4z=4648
5y+4y+4z=4648
(9y+4z=4648)*7/4 to eliminate z
(63/4)y+7z=8134
(63/4)y+5y=8134
(83/4)y= 8134
83y=32536
y=392
4x=5y
4x=1960
x=490
7z=5y
7z=1960
z=280
Therefore, x=490, y=392 and z=280
.
Answered by
0
Answer:
Divide 1162 into three parts such that 4 times the first part, 5 times the second part and 7 times the third part are equal.
A 490, 392, 280
B 492, 392, 380
C 493, 329, 389
D 393, 290, 360
Step-by-step explanation:
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