Question

Divide 117 chocolates among A,B,C in the ratio 1/2 : 1/3 : 1/4

Please provide a detailed step - by - step answer.

Answer 1

Answer:

To convert

2

1

:

3

1

:

4

1

into normal ratio, multiply each fraction by the LCM(2,3,4)=12

=12×

2

1

:12×

3

1

:12×

4

1

= 6:4:3

Thus, A would have got

6+4+3

6

×117=54

B would have got

6+4+3

4

×117=36

And C would have got

6+4+3

3

×117=27

Instead Rs. 117 have been divided in the ratio of 2:3:4

A gets

2+3+4

2

×117=26

B gets

2+3+4

3

×117=39

C gets

2+3+4

4

×117=52

Thus, by changing the ratio,

A gained 26−54 = -28

B gained 39−36 = 3

And C gained 52−27=25

Thus, C's gain of 25 is the most.

Step-by-step explanation:

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Answer 2

Answer:

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Question

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By mistake instead of dividing Rs. 117 among A,B and C into the ratio

2

1

:

3

1

:

4

1

, it was divided in the ratio of 2:3:4 . Who gains the most and by how much?

Medium

Solution

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Correct option is

D

C,Rs.25

To convert

2

1

:

3

1

:

4

1

into normal ratio, multiply each fraction by the LCM(2,3,4)=12

=12×

2

1

:12×

3

1

:12×

4

1

= 6:4:3

Thus, A would have got

6+4+3

6

×117=54

B would have got

6+4+3

4

×117=36

And C would have got

6+4+3

3

×117=27

Instead Rs. 117 have been divided in the ratio of 2:3:4

A gets

2+3+4

2

×117=26

B gets

2+3+4

3

×117=39

C gets

2+3+4

4

×117=52

Thus, by changing the ratio,

A gained 26−54 = -28

B gained 39−36 = 3

And C gained 52−27=25

Thus, C's gain of 25 is the most.