divide 12 into two parts such that sum of their sqaure is 74
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Let x = one of the numbers
Then the other number = 12 - x
Sum of the squares is 74:
x^2 + (12-x)^2 = 74
Solve for x:
x^2 + 144 - 24x + x^2 = 74
2x^2 - 24x + 70 = 0
x^2 - 12x + 35 = 0
Factor:
(x-7)(x-5) = 0
So the numbers are 5 and 7
Then the other number = 12 - x
Sum of the squares is 74:
x^2 + (12-x)^2 = 74
Solve for x:
x^2 + 144 - 24x + x^2 = 74
2x^2 - 24x + 70 = 0
x^2 - 12x + 35 = 0
Factor:
(x-7)(x-5) = 0
So the numbers are 5 and 7
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