Divide 120 into two parts such that one sixth of one part may exceed one fourth of the other part by 10.
Answers
Answered by
2
Answer:
I have no work experience yet but I want to learn and develop my skill
Answered by
3
Answer:
Let the first part = x
Second part = 120 - x
According to the problem given ,
2/3 of first part = 2/5 of second part
2/3 × x = 2/5 × ( 120 - x )
Multiply 1/2 bothsides, we get
x /3 = (120 - x ) /5
5x = 3( 120 - x )
5x = 360 - 3x
5x + 3x = 360
8x = 360
x = 360/8
x = 45
Therefore ,
First part = x = 45
Second part = 120 - x
= 120 - 45
= 75
Step-by-step explanation:
make a brain list answer and follow me please please please please please
Similar questions