divide 120 into two partsso that three times the smaller ome is equal to twise the larger one
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Question:
Divide 120 into two parts, so that three times the smaller one is equal to twice the large one .
Solution:
Let the smaller part be x
and the large part be (120-x).
Now;
According to the question;
Three times the smaller part is equal to twice the large part .
Thus,
=> 3x = 2(120 - x)
=> 3x = 240 - 2x
=> 3x + 2x = 240
=> 5x = 240
=> x = 240/5
=> x = 48
Thus,
Smaller part = x = 48
Larger part = 120 - x = 120 - 48 = 72
Hence,
120 should be divided in the parts 48 and 72.
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