Question

Divide 15 into two parts such that sum of their reciprocal will be 3/10

Answer 1

hope it will help u mark as brainliest answer

Answer 2

Let the two parts be x and y

Then acc to ques

       x + y = 15             ....(1) 
 1/x + 1/y = 3/10         

  x + y/xy = 3/10           ....(2)   

Substituting x = 15- y from eq (1) upon (2)         

    15 - y + y/(15 - y)y = 3/10

                 15/15y -y² = 3/10

                       15(10) = 3(15y - y²)

                            150 = 45y - 3y²

⇒3y² - 45y + 150

Divide by 3 0n whole

⇒y² - 15y + 50

⇒y² - 10y -5y + 50

⇒y(y-10) - 5(y-10)

⇒(y-5)(y-10)

Then y = 10 or 5

If y = 10     x = 5

If y = 5       x =10

:) Hope This Helps!!!