Math, asked by PragyaSingh0011, 1 year ago

Divide 150 into 3 parts such that the second number is fifth sixth of the first and third number is four/5th of the second

Answers

Answered by chandu7077
1
60,50,40
take a,b,c as any parts of 150
b=5/6a
c=4/5b=4/6a=2/3a

ratio=a:5/6a:2/3:a

a+5/6a+2/3a=150

a=60
b=5/6*60=50
c=40

PragyaSingh0011: Please answer my question in one variable.
chandu7077: whatever the variable 150 is divided na into 3 parts according to your qstn
Answered by ssamboy785
0

Answer: 60,50 & 40


Step-by-step explanation: Let the first be x.

Hence, the second no. = 5x/6.

Third no. = 4/5 * 5x/6

= 2x/3.

ATQ,

x + 5x/6 + 2x/3 = 150

= (6x+5x+4x)/6 = 150

= 15x/6 = 150

= 15x = 150*6

= 15x = 900

= x = 900/15 = 60.

Hence the numbers are, 60, 50 & 40.

You will get the answer after replacing 'x' with 60.

Hope it helps


Similar questions