Question

Divide 150 into three equal parts such that the second number is five-sixth the first and the third number is four-fifth the second.

Answer 1

Let the first number be 'x'
Then A/q,
Second number = 5/6 × first number
i.e. 5/6 × x
And,
Third number = 4/5 × second number
i.e. 4/5 × 5/6x

Now, According to question,
First number + second number + third number = 150

x + 5/6x + 4/6x = 150

(6x + 5x + 4x)/6 = 150

15x/6 = 150

15x = 150 × 6

15x = 900

x = 900/15
x = 60

Hence, first number = x = 60

Second number = 5x/6 =(5 × 60)/6
=300/6
=50

And,third number= 4x/6
= (4 × 60)/6
= 240/6
= 40

Therefore the three numbers are 60, 50 and 40.