Question

divide 150 into three parts such that the second numbee is 5/6th of the first and third number is 4/5th of the second

Answer 1

let the 1st no. be x
second no. = 5x/6
third no. = (4/5)×(5x/6)=2x/3
5x/6+2x/3+x=150
x=60
2nd no.=5×60/6=50
3rd no. = 40
hope it helps