Question

Divide 150 into three parts such that the second number is 5/6 of the first and the third number is 4/5 of the second number

Answer 1

Answer:

Let the first number be x

then second number = 5x/6

third number = 4/5 × 5x/6 = 2x/3

now

150 = x+5x/6+2x/3

=> 150 = (6x+5x+4x)/6

=> 150 = 15x/6

=> x = 60

first number = 60

second number = 5x/6 = 5×60/6 = 50

third number = 2x/3 = 2×60/3 = 40

I hope this will help you!!!!!!

Answer 2

Answer:

1st no. = 60

2nd = 50

3rd = 40

Step-by-step explanation:

let first number be

$x$

therefore

2nd=

$\frac{5x}{6}$

3rd =

$\frac{4}{5} \times \frac{5x}{6}$

$= \frac{4x}{6}$

now,

$x + \frac{5x}{6} + \frac{4x}{6} = 150$

$\frac{6x + 5x + 4x}{6} = 150$

$15x = 150 \times 6$

$x = 60$

so,

first number =60

second number=

$\frac{5x}{6} = 50$

third number

$\frac{4x}{6} = 40$

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