Question

Divide 150 into three parts such that the second number is five-sixths the first and the third number is four- fifths the second?​

Answer 1

QUESTION

Divide 150 into three parts such that the second number is five-sixths the first and the third number is four- fifths the second?​

ANSWER

Total Number=150

Let First Part=x

Accoring to Question Second Part is $\mathsf{\frac{5}{6}}$the First.

Second Number=$\mathsf{\frac{5x}{6}}$

Third Number is =$\mathsf{\frac{4}{5}}$ the second.

$\mathsf{\frac{5x}{6}\times\frac{4}{5}}$

Third Number=$\mathsf{\frac{20x}{30}}$

On adding We will get 150

A/Q

$x + \frac{5x}{6} + \frac{20x}{30} = 150 \\ \\ \frac{30x + 5 \times 5x + 20x}{30} = 150 \\ \\ \frac{75x}{30} = 150 \\ \\ x = \frac{30}{\cancel{75}} \times \cancel{150 } \\ \\ x = 30 \times 2 \\ \\ x = 60$

First Part=60

Second part=5/6×60

=50

Third Part=20/30×60

=40

$\boxed{\mathbf{First \:Part=60}}$

$\boxed{\mathbf{Second \:Part=50}}$

$\boxed{\mathbf{Third \:Part=40}}$

Answer 2

Step-by-step explanation:

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