Question

divide 16x3-46x2+39x+9/8x-3​

Answer 1

Answer:

I think you meant $\frac{16x^{3} - 46x^{2} +39x - 9\\}{8x-3}$

The answer for that equation I gave above is $(x-1)(2x-3)$

If you would continue with your equation, we would be left with a remainder of 18

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