Question

Divide 180 in to two parts such that the first part
is twelve less than twice the second part.​

Answer 1

Answer:

$\bf \: let \: second \: part \: be \: x \\ \\ \bf \: 1st \: part = 180 - (2x - 12) \\ \\ acq \\ \\ \sf \: x = 180 - 2x + 12 \\ \sf \: 3x = 192 \\ \sf \: x = 64 \\ \\ \underline{ \boxed{ \red{ \bf \: 2nd \: part = 64}}} \\ \\ \underline{ \boxed{ \purple{ \bf \: 1st \: part \: = 2 \times 64 - 12 = 116}}}$