Math, asked by punamkinhikar, 2 months ago

Divide 180 in to two parts such that the first part
is twelve less than twice the second part.​

Answers

Answered by Anonymous
6

Answer:

 \bf \: let \: second \: part \: be \: x \\  \\  \bf \: 1st \: part = 180 - (2x - 12) \\  \\ acq \\  \\  \sf \: x = 180 - 2x + 12 \\  \sf \: 3x = 192 \\  \sf \: x = 64 \\  \\  \underline{ \boxed{ \red{ \bf \: 2nd \: part = 64}}} \\  \\  \underline{ \boxed{ \purple{ \bf \: 1st \: part \:  = 2 \times 64 - 12 = 116}}}

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