divide 184 into 2 parts such that one third of one part may exceed one seventh of another part by 8
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Let the first part be " x " and second part be " y " .
We have x + y = 184 ...eq(1)
x/3-8 = y/7
7x-3y= 21×8
7x-3y = 168 .---> equation (2)
Multiplying equation (1) by 3 and adding (2)
3x+3y = 552
7x - 3y = 168
============
10x = 720
x = 72.
Substituting in equation (1)
72 + y = 184
y = 184 - 72 = 112 .
Therefore, The required parts are 72 , 112 .
We have x + y = 184 ...eq(1)
x/3-8 = y/7
7x-3y= 21×8
7x-3y = 168 .---> equation (2)
Multiplying equation (1) by 3 and adding (2)
3x+3y = 552
7x - 3y = 168
============
10x = 720
x = 72.
Substituting in equation (1)
72 + y = 184
y = 184 - 72 = 112 .
Therefore, The required parts are 72 , 112 .
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