divide 184 into two parts such that one eight of one part may exceed one sixth of the other by2
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Answer: 72 and 112
Step-by-step explanation:
Let the two parts are x and 184−x.
then, x/3=1/7(184−x)+8
⇒7x=3((184−x)+56)
⇒7x=552−3x+168
⇒10x=720
⇒x=72
So, other part = 184−72=112.
So, two parts are 72 and 112.
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