factorise the 9x2-21x-8
Sanskriti141:
( 3x+1 ) ( 3x-8 )
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Hii there!!!
9x^2 - 21x - 8
= 9x^2 + 3x - 24x - 8
= 3x ( 3x + 1 ) - 8 ( 3x + 1 )
= ( 3x + 1 ) ( 3x - 8 )
Hope it helps.....
9x^2 - 21x - 8
= 9x^2 + 3x - 24x - 8
= 3x ( 3x + 1 ) - 8 ( 3x + 1 )
= ( 3x + 1 ) ( 3x - 8 )
Hope it helps.....
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