Question

divide 184 into two parts such that one third of 1 part may exceed one- seventh of another part by 8

Answer 1

Let one number = x.

Then the other number will be 184 - x.

Given that one-third of 1 part may exceed one-seventh of another part by 8.

1/3 * x = 1/7 * (184 - x) + 8

On cross-multiplication, we get

7x = 3(184 - x) + 21(8)

7x = 552 - 3x + 168

7x + 3x = 552 + 168

10x = 720

x = 72.

1st part = 72.

2nd part = 184 - 72

               = 112.


Verification:

112 + 72 = 184


Therefore the numbers are 72 and 112.


Hope this helps!