Question

divide 184 into two parts such that one third of one part may exceeded one seventh of the other part by 8

Answer 1

assuming 1st part K so 2nd part be (184-K).
then according to conditions
(K÷3)-[(184-K)÷7]=8.
after solving it the K=72
so 1st part =72
2nd part =11


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Answer 2

heya!!

here is your solution -

Let one part be x
Then, other part = (184 – x)

$1 / 3 x = 1 / 7 ( 184 - x ) + 8 \\ \\ 1 / 3 x - 8 = 1 / 7 ( 184 - x ) \\ \\ ( x - 24) / 3 = (184 - x) / 7 \\ \\ 7 x - 168 = 552 - 3 x \\ \\ 10 x = 720 \\ \\ x = 72$

Hence, first part = 72

Second part = 184 - 72 = 112

hope it helps!!