Question

Divide 184 into two parts such that one third of one part may exceed one seventh of another part by 8​

Answer 1

Answer:

Step-by-step explanation:

Let one part be x

other part = (184-x)

1/3rd of one part exceeds 1/7th of the other by 8. Thus

(1/3 × x) - [1/7 × (184-x)] = 8

⇒ x/3 - (184/7 - x/7) = 8

⇒ x/3 - 184/7 + x/7 = 8

⇒ x/3 + x/7 - 184/7 = 8

⇒ x/3 + x/7 = 8 + 184/7

⇒ (7x+3x)/21 = (56+184)/7

⇒ 10x/21 = 240/7

⇒ x = 240/7 × 21/10

⇒ x = 72

So one part = 72

other part = 184 - 72 = 112

Answer 2

Answer:

72 & 112

Step-by-step explanation:

Let one part be x

∴ The other part is (184 – x)

One-third of x = (x/3)

One-seventh of other part    

Given that one-third of one part exceeds one-seventh of other part by 8.

x/3 = [(184-x)/7] + 8

x/3 = (184-x+56)/7

⇒ 7x = 3(240 – x)

⇒ 7x = 720 – 3x

⇒ 10x = 720

∴ x = 72

184-x

=184-72

=112

Hence the two parts 72 and 112.