Math, asked by a1r2y3a4n5singh, 1 year ago

divide 2√2x^4+6√2x^3+x^2 by2√2x^2​

Answers

Answered by sivakumarkdpi14
0

Answer:

√2x^3/2* [2(x^1/2) +6+1/2(x^3/2)]

Step-by-step explanation:

2√2x^4+6√2x^3+x^2 ÷ 2√2x^2

2√2√x^4+6√2√x^3+1/2x^2√2√x^2

2√2x^2+6√2x√x+1/2x^2√2x

2√2x^2+6√2x*(x^1/2)+1/2x^3√2

2√2x^2+6√2(x^3/2)+1/2x^3√2

√2x^3/2* [2(x^1/2) +6+1/2(x^3/2)]

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