please answer this question
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area in 1 revolution = CSA
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radius of roller=112cm/2= 56cm
height of roller=150cm
area levelled= CSA of roller × 500revolution
=2Πrh × 500
= 2×22/7×56×150×500
=2×22×8×150×500
=44×1200×500
=52800×500
= 26400000 cm sq.
hope this will help you✌
height of roller=150cm
area levelled= CSA of roller × 500revolution
=2Πrh × 500
= 2×22/7×56×150×500
=2×22×8×150×500
=44×1200×500
=52800×500
= 26400000 cm sq.
hope this will help you✌
sakshisrivastava39:
thanks
wlc✌
mention not
hahahha..
sakshi i got the answer but don't know how i send u the answer??
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