Question

Divide 207 in three parts, such that all are in A.P. and product of two smaller parts will be 4236.​

Answer 1

Answer:

Let the three parts of 207 in A.P be (a - d) , a , (a + d) where, a > d

Now, clearly, (a + d) > a > (a - d)

Now, A to Q,

(a - d) + a + (a + d) = 207

=> 3a = 207

=> a = 69 --- (i) and,

(a - d) x a = 4623

=> 69 (69 - d) = 4623

=> d = (4761 - 4623)/69 = 2

Hence, a = 69 and d = 2

so, (a - d) = 67, a = 69 and (a + d) = 71

Hence, the three requred parts are, 67, 69 and 71 Ans..!!