divide 207 in three parts such that all parts are in A.P and product of two smaller parts will be 4623
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Let the three parts of 207 in A.P be (a - d) , a , (a + d) where, a > d
Now, clearly, (a + d) > a > (a - d)
Now, A to Q,
(a - d) + a + (a + d) = 207
=> 3a = 207
=> a = 69 --- (i) and,
(a - d) x a = 4623
=> 69 (69 - d) = 4623
=> d = (4761 - 4623)/69 = 2
Hence, a = 69 and d = 2
so, (a - d) = 67, a = 69 and (a + d) = 71
Hence, the three requred parts are, 67, 69 and 71 Ans..!!
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Now, clearly, (a + d) > a > (a - d)
Now, A to Q,
(a - d) + a + (a + d) = 207
=> 3a = 207
=> a = 69 --- (i) and,
(a - d) x a = 4623
=> 69 (69 - d) = 4623
=> d = (4761 - 4623)/69 = 2
Hence, a = 69 and d = 2
so, (a - d) = 67, a = 69 and (a + d) = 71
Hence, the three requred parts are, 67, 69 and 71 Ans..!!
if u like my answer plz give me a brainliest
rjr2:
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