Divide 21 into two parts in such a way that 10 times of one part is one more than 9 times the other
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Answered by
2
x+y=21
10x=9y+1
10x-9y=1
9x+9y=189
19x=190
x=10
y=11
10x=9y+1
10x-9y=1
9x+9y=189
19x=190
x=10
y=11
Answered by
1
x+y=21
10x=9y+1
10x-9y=1
9x+9y=189
19x=190
x=10
y=11
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