Math, asked by BhawanaKriplani, 1 year ago

rationalise the denominator 1 /√5-2

Answers

Answered by Anonymous
63
Heya !!

=1/√5-2 rationalise it
= 1/√5-2×√5+2/√5+2
=√5+2/(√5)^2-(2)^2
=√5+2/5-4
=√5+2 ..

Hope this helps you ☺
Answered by pulakmath007
6

\displaystyle \sf{ \frac{1 }{ \sqrt{5} - 2 } } = \sqrt{5}+2

Given :

\displaystyle \sf{ \frac{1 }{ \sqrt{5} - 2 } }

To find :

To rationalize the denominator

Solution :

Step 1 of 2 :

Write down the given expression

Here the given expression is

\displaystyle \sf{ \frac{1 }{ \sqrt{5} - 2 } }

Step 2 of 2 :

Rationalize the denominator

\displaystyle \sf{ \frac{1 }{ \sqrt{5} - 2 } }

Multiplying both of the numerator and denominator by √5 + 2 we get

\displaystyle \sf{ \frac{1 }{ \sqrt{5} - 2 } }

\displaystyle \sf{ = \frac{1 \times ( \sqrt{5} + 2)}{ (\sqrt{5} - 2)(\sqrt{5} + 2 ) } }

\displaystyle \sf{ = \frac{ (\sqrt{5} + 2 ) }{ {(\sqrt{5} )}^{2} - {( 2 )}^{2} } }

\displaystyle \sf{ = \frac{(\sqrt{5} + 2 ) }{ 5 - 4} }

\displaystyle \sf{ = \frac{ \sqrt{5} + 2 }{1} }

\displaystyle \sf{ = \sqrt{5} + 2 }

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Learn more from Brainly :-

1. the value of (√5+√2)²

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