Question

Divide 232 into two parts such that twice one part is 48 more than six times the other part.

Answer 1

just use the calculator to find the answer

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

GIVEN

Divide 232 into two parts such that twice one part is 48 more than six times the other part

TO DETERMINE

The two parts of 232

CALCULATION

Let first part = x

Second Part = ( 232 - x)

By the given condition

$\sf{ 2x = 6(232 - x) + 48\: }$

$\implies \sf{ 2x = 1392 - 6x + 48\: }$

$\implies \sf{ 2x + 6x = 1392 + 48\: }$

$\implies \sf{ 8x = 1440\: }$

$\displaystyle \: \implies \sf{ x = \frac{1440}{8} \: }$

$\displaystyle \: \implies \sf{ x = 180 \: }$

Hence first part = 180

Second Part = 232 - 180 = 52

So the required two parts are 180 & 52

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LEARN MORE FROM BRAINLY

If a : b=c:d=e: f= 2:1

Then (a + 2c + 3e) : (5b + 10d + 15f) =?

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