divide:(-24×3y3z3)÷6×2y2z
Answers
Answered by
1
Solution :
( -24 × 3y³z³ )/( 6 × 2y²z )
= ( - 12 × 2 × 3 . y².y .z².z )/( 12y²z )
After cancellation , we get
= - 6yz²
••••
( -24 × 3y³z³ )/( 6 × 2y²z )
= ( - 12 × 2 × 3 . y².y .z².z )/( 12y²z )
After cancellation , we get
= - 6yz²
••••
aryansinghrajput72:
thanks
Similar questions
Science,
6 months ago
Social Sciences,
6 months ago
History,
11 months ago
Science,
11 months ago
India Languages,
1 year ago