Question

Divide 24 in three parts such that they are in AP and their product is 40

Answer 1

* There's some correction, the product should be 440.
Let the numbers be a-d,a,a+d:
Now,a-d+a+a+d=24
3a=24,a=8
Now,(8)*(8-d)*(8+d)=440
$64 - {d}^{2} = 55$
d=±3
But according to the question d=3
Numbers are 5,8,11.