Question

Divide 243 into three parts such that half of the first part, one third of the second part and one fourth of the third par are all equal

Answer 1

let first part be a
second part be b
third part be c
a+b+c =243
a/que
a/2=b/3=c/4
a/2=b/3=c/4=x
then a= 2x
b= 3x
c= 4x
2x+ 3x+ 4x = 243
9x = 243
x= 243/9
x= 27
a is 54
b is 81
c is 108