Question

Divide 243 into three parts such that half of the first part ,one-third of the second part and one -fourth of the third part all are equal.............. linear equations in one variable(answer requiredin one variable) pls help

Answer 1

Let parts be a, b and c

According to question

a/2 = b/3 = c/4 ----(1)

From equation 1
a= 2b/3 ----(2)
c = 4b/3 -----(3)

Now,

a+b+c = 243
=> 2b/3 + b +4b/3 = 243
=> 9b/3 = 243
=> 3b = 243
=> b = 81

First part = 54
Second part = 81
Third part = 108

Answer 2

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