divide 26 into 2 parts whose sum of squares is 346
sridharkannan9pc1jre:
can you more clear in question? and mention you need answer in equation form
Answers
Answered by
13
26 can be divided as 15 and 11. sum of squares of 15 and 11 is 225 and 121 , which total gives 346.
assuming X and Y as 15 & 11, it satisfies the equation.
15^2 + 11^2 = 346
225 + 121 = 346
LHS = RHS. (To my knowledge)
Answered by
37
Let one part be x and the other be 26-x
ACQ,
X^2 + (26-X)^2 = 346
X^2 + x^2 + 676 - 52x = 346
2x^2 - 52x + 330 = 0
=> x^2 - 26x + 165 = 0
X^2 - 15x - 11x + 165 =0
X ( x - 15) - 11x (x - 15) =0
(x-15)(x-16) =0
X = 15
X = 11
Therefore the two parts of 26 are 15 and 11
{15 + 11 = 26}
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