Question

Divide 28 into two parts in such a way that 6/5 of one part is equal to 2/3 of the other. find the two parts.

Answer 1

Let the two parts of 28 be x and y.

∴ x + y = 28

⇒ x = 28 - y .........(1)

Also, according to the given condition,

$\frac{6}{5}x = \frac{2}{3}y$

⇒ 18(28 -y) = 10 y [By Cross Multiplying]

⇒ 504 - 18y = 10y

⇒ 18y = 504

⇒ y = 28

Now,
(1)⇒ x = 28 - y

⇒ x = 28 - 28

⇒ x = 0

So, the two parts are 28 and 0.