Question

divide 28 into two parts in such a way that 6/5 of one part is equal to 2/3 of another part

Answer 1

Dear friend,
Let 1st part of 28 = x
Let 2nd part of 28 = 28-x
A/Q
6x/5=2/3* (28-x)
3* (6x)= 10* (28-x)
18x = 280-10x
18x+10x = 280
28x=280
x=280/28
x=10                
 28-x=28-10=18

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Answer 2

Heya mate ,

here is your answer,
______________

Let one part is = x

and other part is = 28 - x

Therefore, according to the question ,

(6/5) x = (2/3) (28-x)

$\frac{6x}{5} = \frac{56}{3} - \frac{2x}{3 } \\ \\ \frac{6x}{5} = \frac{56 - 2x}{3} \\ \\ 18x = 280 - 10x \\ \\ 18x + 10x = 280 \\ \\ 28x = 280 \\ \\ x = \frac{280}{28}$
x = 10 = one part

28 - x = 28 - 10 = 18 = other part

_________________

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