Question

Divide 288 into three parts so that half of the first, one third of the second part & one fourth of the third part will be equal ?

Answer 1

let the nos. be x y z
x+y+z=288
x/2=y/3=z/4=k(say)
x=2k
y=3k
z=4k
2k+3k+4k=288
9k=288
k=31
therefore....
x=2k=62
y=3k=93
z=4k=124