Math, asked by akshaysunil73, 1 year ago

Divide 29 into 2 parts so that the sum of the squares of the parts is 425 ..... Find the parts

Answers

Answered by Anonymous

908

let the two parts be x and y
x + y = 29 ⇒ y = 29 - x
so according to question x² + y² = 425
⇒ x² + (29 - x)² = 425
⇒ x² + 841 + x² - 58x = 425
⇒2x² - 58x + 416 = 0
⇒ x² - 29x + 208 = 0
⇒ x² - 13x - 16x + 208 = 0
⇒ x(x - 13) - 16(x - 13) = 0
⇒ (x - 16)(x - 13) = 0
so x = 16 or 13 ANSWER

Anonymous: hope it helps

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Answered by shivam2000

221

let the two parts be x and y
x + y = 29
y = 29 - x
A.T.Q
x² + y² = 425
x² + (29 - x)² = 425
x² + 841 + x² - 58x = 425
2x² - 58x + 416 = 0
x² - 29x + 208 = 0

By quadratic formula

D=b²-4ac
=841-832= 9

Now x= -b + √D or -b - √D
2a 2a

x= 29 + 3 or 29 - 3
2 2

x= 32 or 26
2 2

x= 16 or x= 13

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