Question

divide 29 into two parts so that the sum of the squares of the two parts is 425.

Answer 1

x2  + (29-x)2  = 425
x2  + 841- 58x + x2  = 4252x2  -58x + 416 = 0x2  - 29x + 208 = 0(x - 13) (x - 16) = 0x = 13, 16

Answer 2

Answer:

Step-by-step explanation:

Let one of the number be ‘a’.

 Given, sum of two numbers is 29 and the sum of their squares is 425

 ⇒ a² + (29 – a)² = 425

 ⇒ a² + 841 + a² – 58a = 425

 ⇒ a² – 29a + 416 = 0

 ⇒ a² – 16a – 13a + 208= 0

 ⇒ a(a – 16) – 13(a – 16) = 0

 ⇒ (a – 13)(a – 16) = 0

 ⇒ a = 13, 16

Thus one number is 13 and the other is 16.