Divide 29 into two parts so that the sum of the squares of the two parts is 425.
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Let the two parts be x and y
x + y = 29 ⇒ y = 29 - x
so according to question x² + y² = 425
⇒ x² + (29 - x)² = 425
⇒ x² + 841 + x² - 58x = 425
⇒2x² - 58x + 416 = 0
⇒ x² - 29x + 208 = 0
⇒ x² - 13x - 16x + 208 = 0
⇒ x(x - 13) - 16(x - 13) = 0
⇒ (x - 16)(x - 13) = 0
so x = 16 or 13 ANSWER
x + y = 29 ⇒ y = 29 - x
so according to question x² + y² = 425
⇒ x² + (29 - x)² = 425
⇒ x² + 841 + x² - 58x = 425
⇒2x² - 58x + 416 = 0
⇒ x² - 29x + 208 = 0
⇒ x² - 13x - 16x + 208 = 0
⇒ x(x - 13) - 16(x - 13) = 0
⇒ (x - 16)(x - 13) = 0
so x = 16 or 13 ANSWER
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