Question

divide 29 into two such parts so that the sum of their squares is 425​

Answer 1

Let the parts be x and 29 – x

According to the problem

x2 + (29 – x)2 = 425

⇒   x2 + 841 + x2 – 58x – 425 = 0

⇒   2x2  - 58x + 416 = 0

⇒ x2 – 29x + 208 = 0

⇒ x2 – 16x – 13x  + 208 = 0

⇒ x(x - 16) – 13(x – 16) = 0

⇒ (x - 16)(x – 13) = 0

⇒  x – 16 = 0 or  x – 13 = 0

⇒ x = 16  or x = 13

[ When x = 16   Then 29 – x = 13 ]

[ When x = 13   Then 29 – x = 16 ]

Hence, the parts are 16 and 13.

●Mark me as brainliest

●Follow me

Answer 2

HEY MATE HERE IS YOUR ANSWER ✍✍

Let the two parts be x and y

x + y = 29 ⇒ y = 29 - x

so according to question x² + y² = 425

⇒ x² + (29 - x)² = 425

⇒ x² + 841 + x² - 58x = 425

⇒2x² - 58x + 416 = 0

⇒ x² - 29x + 208 = 0

⇒ x² - 13x - 16x + 208 = 0

⇒ x(x - 13) - 16(x - 13) = 0

⇒ (x - 16)(x -  13) = 0

 so x = 16 or 13  

HOPE THIS WORKS ✌