Question

divide 2x^4 + 4x^2 + 4x-x^3 -7 by x-1​

Answer 1

Answer:-

x - 1 = 0

x = 0 + 1

x = 1

Let p(x) = 2x^4 + 4x^2 + 4x - x^3 - 7

Substituting Value of x in the above equation.

p(1) = 2 (1)^4 + 4 (1) ^2 + 4(1) - (1) ^3 - 7

p(1) = 2 (1) + 4 (1) + 4 - 1 - 7

p(1) = 2 + 4 + 4 - 1 - 7

p(1) = 2 +8 - 8

p(1) = 2 + 0

p(1) = 2

So by Factor theorem when we divide 2x^4 + 4x^2 + 4x - x^3 - 7 by x - 1 we get the answer as 2.