Math, asked by santoshksahu02, 1 year ago

Divide (2x square+x-20) by (x+3) and verify division algorithm.

Answers

Answered by chaitanyadamaraju
57
2x^2+x-20/X+3=
2x-5+remainder=-5

division algorithm:-
a=bq+r
therefore
x+3×2x-5=2x^2-5x+6x-15
now add remainder to get 2x^2+x-20 which is our a
therefore LHS=RHS
Therefore satisfied




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Answered by sksk76106
39

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