Divide (2x square+x-20) by (x+3) and verify division algorithm.
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57
2x^2+x-20/X+3=
2x-5+remainder=-5
division algorithm:-
a=bq+r
therefore
x+3×2x-5=2x^2-5x+6x-15
now add remainder to get 2x^2+x-20 which is our a
therefore LHS=RHS
Therefore satisfied
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2x-5+remainder=-5
division algorithm:-
a=bq+r
therefore
x+3×2x-5=2x^2-5x+6x-15
now add remainder to get 2x^2+x-20 which is our a
therefore LHS=RHS
Therefore satisfied
please mark it as brainliest
chaitanyadamaraju:
Mark as brainliest
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