Question

for root 2 x square - 5 x + root 2 is equals to zero find the value of the discriminant

Answer 1

discriminant = b^2-4ac
equation =2x^2-5x+√2

-5^2-4*2*√2
25-8√2
multiply 2on both sides
50-16
=34>0
therefore it has distinct roots

Answer 2

Hey

Here is your answer,

√2 x^2 - 5x + √2 =0

a = √2
b = -5
c = √2

b^2 - 4ac = (-5)^2 - 4x√2x√2
=25 - 4 x 2
=25-8
17>0

It has distinct real roots.

Hope it helps you!