Question

divide 2x³-4x⁴+3x²-1 by x²+2 and verify the division algorithm​

Answer 1

Answer:

On dividing we get quotient as (-4x²+2x+11) and remainder (-23)

Step-by-step explanation:

As (2x³-4x⁴+3x²-1) isn't arranged in proper order we first change it to (-4x⁴+2x³+3x²-1) and divide it with (x²+2).

x²+2)-4x⁴+2x³+3x²-1(-4x²+2x+11

-4x⁴- 0 -8x²

+ +

————————

2x³-11x²-1

2x³+0 +0

-

——————

-11x²-1

-11x²+22

+ -

—————

-23

Division algorithm is DIVIDEND=DIVISOR*QUOTIENT+REMAINDER

=>(x²+2)(-4x²+2x+11)+(-23)

=>(-4x⁴+2x³+3x²-1)

Hope it helps ;)