Question

divide 2x³-x²-3x+5 by 2x-1​

Answer 1

Answer:

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Answer 2

Answer:

Dividing a polynomial (2x³-x²-3x+5) with a binomial (2x-1), the quotient is x²-3/2 and the remainder is 7/2.

Step-by-step explanation:

              2x-1​  |¦ 2x³-x²-3x+5 |¦ x²-3/2            

                          2x³-x²

                          __________

                                    - 3x+5

                                    - 3x+3/2

                               _________

                                       7/2

Step 1. Divide the first term of the dividend (2x³) by the first term of the divisor (2x), and put that as the first term in the quotient (x²).

Step 2. Multiply the divisor by that answer, and place the product (2x³-x²) below the dividend.

Step 3. Subtract the polynomials we get 0.

Step 4. Repeat the same process with the new polynomial (-3x+5).

Step 5. when we are dividing a polynomial (2x³-x²-3x+5) with a binomial (2x-1), then the quotient is x²-3/2 and the remainder is 7/2.