Math, asked by mydreamnasa, 8 months ago

divide 2x⁴ + 5x³ - 3x² + 4x + 1 by x+1​

Answers

Answered by MansiMalewar
2

Step-by-step explanation:

=> x+1= 0

=> x+1= 0 x=-1

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1 P(-1)= 2(-1)^4+ 5(-1)^3 -3(-1)^2 +4(-1) +1

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1 P(-1)= 2(-1)^4+ 5(-1)^3 -3(-1)^2 +4(-1) +1 = 2 -5 -3 -4 +1

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1 P(-1)= 2(-1)^4+ 5(-1)^3 -3(-1)^2 +4(-1) +1 = 2 -5 -3 -4 +1 = 3 - 12

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1 P(-1)= 2(-1)^4+ 5(-1)^3 -3(-1)^2 +4(-1) +1 = 2 -5 -3 -4 +1 = 3 - 12 = 9

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1 P(-1)= 2(-1)^4+ 5(-1)^3 -3(-1)^2 +4(-1) +1 = 2 -5 -3 -4 +1 = 3 - 12 = 9Remainder is 9

=> x+1= 0 x=-1 P(x)= 2x^4 +5x^3 -3x^2 +4x + 1 P(-1)= 2(-1)^4+ 5(-1)^3 -3(-1)^2 +4(-1) +1 = 2 -5 -3 -4 +1 = 3 - 12 = 9Remainder is 9.°. 2x^4 +5x^3 -3x^2 +4x + 1 can't be divisible by x+1

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