Question

Divide 32 into four parts which are the four terms of an AP such that the
product of the first and the fourth terms is to the product of the second
and the third terms as 7:15.

Answer 1

let the four no. be a+d,a-d,a+3d,a-3d

a+d+a-d+a+3d+a-3d=32

4a=32

a=8

(a+3d)(a-3d)/(a+d)(a-d)=7:15

a²-9d²/a²-d²=7:15

putting value of a and solve it

you will get the answer