Question

Divide (32x4y3 – 16x4y4) by (–8x2y).​

Answer 1

Answer:

$\frac{32 {x}^{4} {y}^{3} - 16 {x}^{4} {y}^{4} }{ - 8 {x}^{2}y } \\ = \frac{ - 8 {x}^{2}y( - 4 {x}^{2} {y}^{2} + 2 {x}^{2} {y}^{3} )}{ - 8 {x}^{2}y } \\ = - 4{x}^{2} {y}^{2} + 2 {x}^{2} {y}^{3}$