Divide 36×4 parts so that if two is added to the first part two is subtracted from the second part the third part is multiplied by two and the fourth part is divided by two then the resulting Number is the same in each case
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Let first part be a, second part be b, third part be c and fourth part be d.
a+b+c+d=36
a+2=b-2=c*2=d/2
a=2c-2
b=2c+2
d=4c
2c-2+2c+2+c+4c=36
c=4
a=6
b=10
d=16
a+b+c+d=36
a+2=b-2=c*2=d/2
a=2c-2
b=2c+2
d=4c
2c-2+2c+2+c+4c=36
c=4
a=6
b=10
d=16
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