Question

divide 36 in two parts in such a way that 1/5 of one part is equal to 1/7 of the other

Answer 1

let the two parts be x and y

ATQ,

x + y =36 .........(i)

Also,

x/5=y/7

7x-5y=0 .........(ii)

multiplying eqn(i) by 5,

5x+5y=180 .........(iii)

Adding eqn (ii) and (iii),

12x=180

x=15

putting in eq (i)

15+y=36

y=21

So,the no. are 15 and 21

Answer 2

Answer:

let the first part be x and the second part be 36-x

according to the question

1/5 * x = 1/7 ( 36 - x)

x/5 = 36 - x/7

7 * x = 5 ( 36 - x)

7x = 180 - 5x

7x + 5x =  180

12x = 180

x = 15

first part = 15

second part = 21

Step-by-step explanation: